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118833143713 is a prime number
BaseRepresentation
bin110111010101100000…
…0011101111110100001
3102100201200112011120221
41232223000131332201
53421332241044323
6130331410403041
711404540025014
oct1565300357641
9370650464527
10118833143713
1146440236789
121b044b90481
13b28a528a6b
145a743a337b
15315781555d
hex1bab01dfa1

118833143713 has 2 divisors, whose sum is σ = 118833143714. Its totient is φ = 118833143712.

The previous prime is 118833143687. The next prime is 118833143747. The reversal of 118833143713 is 317341338811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117836352529 + 996791184 = 343273^2 + 31572^2 .

It is a cyclic number.

It is not a de Polignac number, because 118833143713 - 213 = 118833135521 is a prime.

It is a super-2 number, since 2×1188331437132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 118833143713.

It is not a weakly prime, because it can be changed into another prime (118833143783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59416571856 + 59416571857.

It is an arithmetic number, because the mean of its divisors is an integer number (59416571857).

Almost surely, 2118833143713 is an apocalyptic number.

It is an amenable number.

118833143713 is a deficient number, since it is larger than the sum of its proper divisors (1).

118833143713 is an equidigital number, since it uses as much as digits as its factorization.

118833143713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145152, while the sum is 43.

The spelling of 118833143713 in words is "one hundred eighteen billion, eight hundred thirty-three million, one hundred forty-three thousand, seven hundred thirteen".