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1189344941761 is a prime number
BaseRepresentation
bin10001010011101010011…
…110111001011011000001
311012200220111100001212211
4101103222132321123001
5123441234301114021
62310213313422121
7151633035126214
oct21235236713301
94180814301784
101189344941761
11419442239139
1217260526a941
1388201c95112
14417c93a977b
1520e0e5863e1
hex114ea7b96c1

1189344941761 has 2 divisors, whose sum is σ = 1189344941762. Its totient is φ = 1189344941760.

The previous prime is 1189344941717. The next prime is 1189344941767. The reversal of 1189344941761 is 1671494439811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1177917331761 + 11427610000 = 1085319^2 + 106900^2 .

It is a cyclic number.

It is not a de Polignac number, because 1189344941761 - 27 = 1189344941633 is a prime.

It is a super-2 number, since 2×11893449417612 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1189344941696 and 1189344941705.

It is not a weakly prime, because it can be changed into another prime (1189344941767) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 594672470880 + 594672470881.

It is an arithmetic number, because the mean of its divisors is an integer number (594672470881).

Almost surely, 21189344941761 is an apocalyptic number.

It is an amenable number.

1189344941761 is a deficient number, since it is larger than the sum of its proper divisors (1).

1189344941761 is an equidigital number, since it uses as much as digits as its factorization.

1189344941761 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5225472, while the sum is 58.

The spelling of 1189344941761 in words is "one trillion, one hundred eighty-nine billion, three hundred forty-four million, nine hundred forty-one thousand, seven hundred sixty-one".