Base | Representation |
---|---|
bin | 110111011101001100… |
… | …1011100011110101001 |
3 | 102101101200101101020011 |
4 | 1232322121130132221 |
5 | 3422344341140132 |
6 | 130413152531521 |
7 | 11414123524225 |
oct | 1567231343651 |
9 | 371350341204 |
10 | 119091349417 |
11 | 46562a64527 |
12 | 1b0b7550ba1 |
13 | b2cbb823c1 |
14 | 5a9a7b7785 |
15 | 317031ab47 |
hex | 1bba65c7a9 |
119091349417 has 2 divisors, whose sum is σ = 119091349418. Its totient is φ = 119091349416.
The previous prime is 119091349367. The next prime is 119091349471. The reversal of 119091349417 is 714943190911.
Together with next prime (119091349471) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 117714865216 + 1376484201 = 343096^2 + 37101^2 .
It is a cyclic number.
It is not a de Polignac number, because 119091349417 - 219 = 119090825129 is a prime.
It is not a weakly prime, because it can be changed into another prime (119091749417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59545674708 + 59545674709.
It is an arithmetic number, because the mean of its divisors is an integer number (59545674709).
Almost surely, 2119091349417 is an apocalyptic number.
It is an amenable number.
119091349417 is a deficient number, since it is larger than the sum of its proper divisors (1).
119091349417 is an equidigital number, since it uses as much as digits as its factorization.
119091349417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 49.
The spelling of 119091349417 in words is "one hundred nineteen billion, ninety-one million, three hundred forty-nine thousand, four hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •