11933679497 has 4 divisors (see below), whose sum is σ = 11933903940. Its totient is φ = 11933455056.

The previous prime is 11933679469. The next prime is 11933679517. The reversal of 11933679497 is 79497633911.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 79497633911 = 1433 ⋅55476367.

It can be written as a sum of positive squares in 2 ways, for example, as 1280136841 + 10653542656 = 35779^2 + 103216^2 .

It is a cyclic number.

It is not a de Polignac number, because 11933679497 - 2¹⁶ = 11933613961 is a prime.

It is a super-3 number, since 3×11933679497³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11933679997) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17579 + ... + 155487.

It is an arithmetic number, because the mean of its divisors is an integer number (2983475985).

Almost surely, 2^11933679497 is an apocalyptic number.

It is an amenable number.

11933679497 is a deficient number, since it is larger than the sum of its proper divisors (224443).

11933679497 is an equidigital number, since it uses as much as digits as its factorization.

11933679497 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224442.

The product of its digits is 7715736, while the sum is 59.

The spelling of 11933679497 in words is "eleven billion, nine hundred thirty-three million, six hundred seventy-nine thousand, four hundred ninety-seven".