Base | Representation |
---|---|
bin | 10110001110110110… |
… | …00101011000111011 |
3 | 1010210211010102001221 |
4 | 23013123011120323 |
5 | 143421014404124 |
6 | 5252211252511 |
7 | 601530531520 |
oct | 130733053073 |
9 | 33724112057 |
10 | 11935700539 |
11 | 5075434524 |
12 | 23912aa137 |
13 | 1182a408c9 |
14 | 813281147 |
15 | 49ccbdce4 |
hex | 2c76c563b |
11935700539 has 4 divisors (see below), whose sum is σ = 13640800624. Its totient is φ = 10230600456.
The previous prime is 11935700509. The next prime is 11935700563. The reversal of 11935700539 is 93500753911.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 93500753911 = 37 ⋅2527047403.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11935700539 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11935700495 and 11935700504.
It is not an unprimeable number, because it can be changed into a prime (11935700509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852550032 + ... + 852550045.
It is an arithmetic number, because the mean of its divisors is an integer number (3410200156).
Almost surely, 211935700539 is an apocalyptic number.
11935700539 is a deficient number, since it is larger than the sum of its proper divisors (1705100085).
11935700539 is an equidigital number, since it uses as much as digits as its factorization.
11935700539 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1705100084.
The product of its (nonzero) digits is 127575, while the sum is 43.
The spelling of 11935700539 in words is "eleven billion, nine hundred thirty-five million, seven hundred thousand, five hundred thirty-nine".
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