11936645756473 has 4 divisors (see below), whose sum is σ = 11936858590800. Its totient is φ = 11936432922148.

The previous prime is 11936645756471. The next prime is 11936645756491. The reversal of 11936645756473 is 37465754663911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11936645756473 - 2¹ = 11936645756471 is a prime.

It is a Smith number, since the sum of its digits (67) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11936645756399 and 11936645756408.

It is not an unprimeable number, because it can be changed into a prime (11936645756471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106333015 + ... + 106445212.

It is an arithmetic number, because the mean of its divisors is an integer number (2984214647700).

Almost surely, 2^{11936645756473} is an apocalyptic number.

It is an amenable number.

11936645756473 is a deficient number, since it is larger than the sum of its proper divisors (212834327).

11936645756473 is an equidigital number, since it uses as much as digits as its factorization.

11936645756473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212834326.

The product of its digits is 342921600, while the sum is 67.

The spelling of 11936645756473 in words is "eleven trillion, nine hundred thirty-six billion, six hundred forty-five million, seven hundred fifty-six thousand, four hundred seventy-three".