Base | Representation |
---|---|
bin | 10110001111000011… |
… | …00010101001011001 |
3 | 1010210221022102000121 |
4 | 23013201202221121 |
5 | 143421433040431 |
6 | 5252311433241 |
7 | 601551111514 |
oct | 130741425131 |
9 | 33727272017 |
10 | 11937393241 |
11 | 5076390254 |
12 | 2391985821 |
13 | 11831b41c7 |
14 | 8135a1d7b |
15 | 49d005611 |
hex | 2c7862a59 |
11937393241 has 4 divisors (see below), whose sum is σ = 12139722000. Its totient is φ = 11735064484.
The previous prime is 11937393203. The next prime is 11937393263. The reversal of 11937393241 is 14239373911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14239373911 = 7 ⋅2034196273.
It is a cyclic number.
It is not a de Polignac number, because 11937393241 - 215 = 11937360473 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11937493241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101164291 + ... + 101164408.
It is an arithmetic number, because the mean of its divisors is an integer number (3034930500).
Almost surely, 211937393241 is an apocalyptic number.
It is an amenable number.
11937393241 is a deficient number, since it is larger than the sum of its proper divisors (202328759).
11937393241 is an equidigital number, since it uses as much as digits as its factorization.
11937393241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202328758.
The product of its digits is 122472, while the sum is 43.
The spelling of 11937393241 in words is "eleven billion, nine hundred thirty-seven million, three hundred ninety-three thousand, two hundred forty-one".
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