Base | Representation |
---|---|
bin | 10110001111011010… |
… | …10101101100110001 |
3 | 1010211011010112101220 |
4 | 23013231111230301 |
5 | 143423231022222 |
6 | 5252502015253 |
7 | 601616312232 |
oct | 130755255461 |
9 | 33734115356 |
10 | 11940485937 |
11 | 50781028a6 |
12 | 2392a17529 |
13 | 1183a27ac3 |
14 | 813b69089 |
15 | 49d416b5c |
hex | 2c7b55b31 |
11940485937 has 8 divisors (see below), whose sum is σ = 15972507936. Its totient is φ = 7934393952.
The previous prime is 11940485929. The next prime is 11940485939. The reversal of 11940485937 is 73958404911.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11940485937 - 23 = 11940485929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11940485937.
It is not an unprimeable number, because it can be changed into a prime (11940485939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6481428 + ... + 6483269.
It is an arithmetic number, because the mean of its divisors is an integer number (1996563492).
Almost surely, 211940485937 is an apocalyptic number.
It is an amenable number.
11940485937 is a deficient number, since it is larger than the sum of its proper divisors (4032021999).
11940485937 is a wasteful number, since it uses less digits than its factorization.
11940485937 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12965007.
The product of its (nonzero) digits is 1088640, while the sum is 51.
The spelling of 11940485937 in words is "eleven billion, nine hundred forty million, four hundred eighty-five thousand, nine hundred thirty-seven".
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