11946390400993 has 2 divisors, whose sum is σ = 11946390400994. Its totient is φ = 11946390400992.

The previous prime is 11946390400837. The next prime is 11946390401017. The reversal of 11946390400993 is 39900409364911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9896705685409 + 2049684715584 = 3145903^2 + 1431672^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11946390400993 is a prime.

It is a super-2 number, since 2×11946390400993² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11946390400193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5973195200496 + 5973195200497.

It is an arithmetic number, because the mean of its divisors is an integer number (5973195200497).

Almost surely, 2^{11946390400993} is an apocalyptic number.

It is an amenable number.

11946390400993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11946390400993 is an equidigital number, since it uses as much as digits as its factorization.

11946390400993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5668704, while the sum is 58.

The spelling of 11946390400993 in words is "eleven trillion, nine hundred forty-six billion, three hundred ninety million, four hundred thousand, nine hundred ninety-three".