Base | Representation |
---|---|
bin | 10110010000101000… |
… | …01011110010100011 |
3 | 1010211212021212220000 |
4 | 23020110023302203 |
5 | 143433332401323 |
6 | 5253504151043 |
7 | 602102003322 |
oct | 131024136243 |
9 | 33755255800 |
10 | 11950668963 |
11 | 5082928522 |
12 | 2396308483 |
13 | 1185b81a6c |
14 | 81525a0b9 |
15 | 49e278e43 |
hex | 2c850bca3 |
11950668963 has 40 divisors (see below), whose sum is σ = 18852622800. Its totient is φ = 7523373312.
The previous prime is 11950668943. The next prime is 11950668973. The reversal of 11950668963 is 36986605911.
11950668963 is a `hidden beast` number, since 1 + 19 + 506 + 68 + 9 + 63 = 666.
It is not a de Polignac number, because 11950668963 - 224 = 11933891747 is a prime.
It is a super-3 number, since 3×119506689633 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (11950668913) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 469303 + ... + 494111.
It is an arithmetic number, because the mean of its divisors is an integer number (471315570).
Almost surely, 211950668963 is an apocalyptic number.
11950668963 is a deficient number, since it is larger than the sum of its proper divisors (6901953837).
11950668963 is a wasteful number, since it uses less digits than its factorization.
11950668963 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25153 (or 25144 counting only the distinct ones).
The product of its (nonzero) digits is 2099520, while the sum is 54.
The spelling of 11950668963 in words is "eleven billion, nine hundred fifty million, six hundred sixty-eight thousand, nine hundred sixty-three".
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