Base | Representation |
---|---|
bin | 110111101001101000… |
… | …0001100110100101001 |
3 | 102102110202001112020222 |
4 | 1233103100030310221 |
5 | 3424223114401033 |
6 | 130522410455425 |
7 | 11430346161056 |
oct | 1572320146451 |
9 | 372422045228 |
10 | 119508356393 |
11 | 46757395a98 |
12 | 1b1b3134575 |
13 | b3673999aa |
14 | 5ad9d2802d |
15 | 3196c3d598 |
hex | 1bd340cd29 |
119508356393 has 2 divisors, whose sum is σ = 119508356394. Its totient is φ = 119508356392.
The previous prime is 119508356333. The next prime is 119508356399. The reversal of 119508356393 is 393653805911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106633596304 + 12874760089 = 326548^2 + 113467^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-119508356393 is a prime.
It is not a weakly prime, because it can be changed into another prime (119508356399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59754178196 + 59754178197.
It is an arithmetic number, because the mean of its divisors is an integer number (59754178197).
Almost surely, 2119508356393 is an apocalyptic number.
It is an amenable number.
119508356393 is a deficient number, since it is larger than the sum of its proper divisors (1).
119508356393 is an equidigital number, since it uses as much as digits as its factorization.
119508356393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2624400, while the sum is 53.
The spelling of 119508356393 in words is "one hundred nineteen billion, five hundred eight million, three hundred fifty-six thousand, three hundred ninety-three".
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