Base | Representation |
---|---|
bin | 1010110111101100111010… |
… | …0101011101001110011011 |
3 | 1120022121100221210220110002 |
4 | 2231323032211131032123 |
5 | 3031310312111134003 |
6 | 41230411451243215 |
7 | 2342336211523523 |
oct | 255731645351633 |
9 | 46277327726402 |
10 | 11952064943003 |
11 | 389892a086019 |
12 | 141048244950b |
13 | 6890c86b5033 |
14 | 2d46a9610683 |
15 | 15ad799baa88 |
hex | adece95d39b |
11952064943003 has 2 divisors, whose sum is σ = 11952064943004. Its totient is φ = 11952064943002.
The previous prime is 11952064942981. The next prime is 11952064943047. The reversal of 11952064943003 is 30034946025911.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11952064943003 is a prime.
It is a super-2 number, since 2×119520649430032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11952064940003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5976032471501 + 5976032471502.
It is an arithmetic number, because the mean of its divisors is an integer number (5976032471502).
Almost surely, 211952064943003 is an apocalyptic number.
11952064943003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11952064943003 is an equidigital number, since it uses as much as digits as its factorization.
11952064943003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 699840, while the sum is 47.
The spelling of 11952064943003 in words is "eleven trillion, nine hundred fifty-two billion, sixty-four million, nine hundred forty-three thousand, three".
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