Base | Representation |
---|---|
bin | 10110010001001000… |
… | …10101001111000001 |
3 | 1010212011020221110102 |
4 | 23020210111033001 |
5 | 143440423330303 |
6 | 5254135012145 |
7 | 602152663361 |
oct | 131044251701 |
9 | 33764227412 |
10 | 11954901953 |
11 | 5085259865 |
12 | 239780a055 |
13 | 1186a046a7 |
14 | 815a3c9a1 |
15 | 49e813288 |
hex | 2c89153c1 |
11954901953 has 2 divisors, whose sum is σ = 11954901954. Its totient is φ = 11954901952.
The previous prime is 11954901943. The next prime is 11954901961. The reversal of 11954901953 is 35910945911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6659865664 + 5295036289 = 81608^2 + 72767^2 .
It is a cyclic number.
It is not a de Polignac number, because 11954901953 - 28 = 11954901697 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11954901898 and 11954901907.
It is not a weakly prime, because it can be changed into another prime (11954901943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5977450976 + 5977450977.
It is an arithmetic number, because the mean of its divisors is an integer number (5977450977).
Almost surely, 211954901953 is an apocalyptic number.
It is an amenable number.
11954901953 is a deficient number, since it is larger than the sum of its proper divisors (1).
11954901953 is an equidigital number, since it uses as much as digits as its factorization.
11954901953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 218700, while the sum is 47.
The spelling of 11954901953 in words is "eleven billion, nine hundred fifty-four million, nine hundred one thousand, nine hundred fifty-three".
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