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11956553113 = 28607417959
BaseRepresentation
bin10110010001010101…
…01000010110011001
31010212021100211102111
423020222220112121
5143441334144423
65254234232321
7602203011301
oct131052502631
933767324374
1011956553113
11508618735a
1223982856a1
1311871620cb
14815d4c601
1549ea3c60d
hex2c8aa8599

11956553113 has 4 divisors (see below), whose sum is σ = 11956999680. Its totient is φ = 11956106548.

The previous prime is 11956553047. The next prime is 11956553143. The reversal of 11956553113 is 31135565911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11956553113 - 217 = 11956422041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11956553143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180373 + ... + 237586.

It is an arithmetic number, because the mean of its divisors is an integer number (2989249920).

Almost surely, 211956553113 is an apocalyptic number.

It is an amenable number.

11956553113 is a deficient number, since it is larger than the sum of its proper divisors (446567).

11956553113 is an equidigital number, since it uses as much as digits as its factorization.

11956553113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446566.

The product of its digits is 60750, while the sum is 40.

The spelling of 11956553113 in words is "eleven billion, nine hundred fifty-six million, five hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 28607 417959 11956553113