Base | Representation |
---|---|
bin | 10110010001111000… |
… | …00001101110000001 |
3 | 1010212120221112001201 |
4 | 23020330001232001 |
5 | 143444021112343 |
6 | 5254520101201 |
7 | 602256533641 |
oct | 131074015601 |
9 | 33776845051 |
10 | 11961113473 |
11 | 5088811651 |
12 | 2399904801 |
13 | 118809aa4a |
14 | 8167b8521 |
15 | 4a013d94d |
hex | 2c8f01b81 |
11961113473 has 4 divisors (see below), whose sum is σ = 11962063408. Its totient is φ = 11960163540.
The previous prime is 11961113401. The next prime is 11961113513. The reversal of 11961113473 is 37431116911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11961113473 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11961173473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455823 + ... + 481348.
It is an arithmetic number, because the mean of its divisors is an integer number (2990515852).
Almost surely, 211961113473 is an apocalyptic number.
It is an amenable number.
11961113473 is a deficient number, since it is larger than the sum of its proper divisors (949935).
11961113473 is an equidigital number, since it uses as much as digits as its factorization.
11961113473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 949934.
The product of its digits is 13608, while the sum is 37.
The spelling of 11961113473 in words is "eleven billion, nine hundred sixty-one million, one hundred thirteen thousand, four hundred seventy-three".
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