Base | Representation |
---|---|
bin | 10110010001111010… |
… | …11100110111110001 |
3 | 1010212121122111012212 |
4 | 23020331130313301 |
5 | 143444120034313 |
6 | 5254532101505 |
7 | 602262650312 |
oct | 131075346761 |
9 | 33777574185 |
10 | 11961486833 |
11 | 5088a4710a |
12 | 2399a64895 |
13 | 118819b97a |
14 | 816874609 |
15 | 4a01b43a8 |
hex | 2c8f5cdf1 |
11961486833 has 2 divisors, whose sum is σ = 11961486834. Its totient is φ = 11961486832.
The previous prime is 11961486787. The next prime is 11961486847. The reversal of 11961486833 is 33868416911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11657089024 + 304397809 = 107968^2 + 17447^2 .
It is a cyclic number.
It is not a de Polignac number, because 11961486833 - 232 = 7666519537 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11961486883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5980743416 + 5980743417.
It is an arithmetic number, because the mean of its divisors is an integer number (5980743417).
Almost surely, 211961486833 is an apocalyptic number.
It is an amenable number.
11961486833 is a deficient number, since it is larger than the sum of its proper divisors (1).
11961486833 is an equidigital number, since it uses as much as digits as its factorization.
11961486833 is an evil number, because the sum of its binary digits is even.
The product of its digits is 746496, while the sum is 50.
The spelling of 11961486833 in words is "eleven billion, nine hundred sixty-one million, four hundred eighty-six thousand, eight hundred thirty-three".
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