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1196312592457 is a prime number
BaseRepresentation
bin10001011010001001110…
…010011000000001001001
311020100220002012101202201
4101122021302120001021
5124100022010424312
62313324534400201
7152300512153513
oct21321162300111
94210802171681
101196312592457
114213982a8244
12173a2a800061
1388a72682958
1441c8a904bb3
15211bb110557
hex11689c98049

1196312592457 has 2 divisors, whose sum is σ = 1196312592458. Its totient is φ = 1196312592456.

The previous prime is 1196312592367. The next prime is 1196312592481. The reversal of 1196312592457 is 7542952136911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1044696586816 + 151616005641 = 1022104^2 + 389379^2 .

It is a cyclic number.

It is not a de Polignac number, because 1196312592457 - 231 = 1194165108809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1196312592398 and 1196312592407.

It is not a weakly prime, because it can be changed into another prime (1196312592557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 598156296228 + 598156296229.

It is an arithmetic number, because the mean of its divisors is an integer number (598156296229).

Almost surely, 21196312592457 is an apocalyptic number.

It is an amenable number.

1196312592457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1196312592457 is an equidigital number, since it uses as much as digits as its factorization.

1196312592457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4082400, while the sum is 55.

The spelling of 1196312592457 in words is "one trillion, one hundred ninety-six billion, three hundred twelve million, five hundred ninety-two thousand, four hundred fifty-seven".