Base | Representation |
---|---|
bin | 1010111000100101000110… |
… | …1010011001011011010011 |
3 | 1120101001022012001010101221 |
4 | 2232021101222121123103 |
5 | 3032032210113032342 |
6 | 41241344330105511 |
7 | 2343412051520065 |
oct | 256112152313323 |
9 | 46331265033357 |
10 | 11967148955347 |
11 | 38a426a669823 |
12 | 1413391b7b297 |
13 | 68a660767821 |
14 | 2d52daa63735 |
15 | 15b45dd77a67 |
hex | ae251a996d3 |
11967148955347 has 2 divisors, whose sum is σ = 11967148955348. Its totient is φ = 11967148955346.
The previous prime is 11967148955341. The next prime is 11967148955369. The reversal of 11967148955347 is 74355984176911.
11967148955347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11967148955347 - 219 = 11967148431059 is a prime.
It is not a weakly prime, because it can be changed into another prime (11967148955341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5983574477673 + 5983574477674.
It is an arithmetic number, because the mean of its divisors is an integer number (5983574477674).
Almost surely, 211967148955347 is an apocalyptic number.
11967148955347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11967148955347 is an equidigital number, since it uses as much as digits as its factorization.
11967148955347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 228614400, while the sum is 70.
The spelling of 11967148955347 in words is "eleven trillion, nine hundred sixty-seven billion, one hundred forty-eight million, nine hundred fifty-five thousand, three hundred forty-seven".
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