Base | Representation |
---|---|
bin | 10110010010101110… |
… | …01100101101000001 |
3 | 1010220002100101211002 |
4 | 23021113030231001 |
5 | 144002332030403 |
6 | 5255332501345 |
7 | 602404221233 |
oct | 131127145501 |
9 | 33802311732 |
10 | 11968236353 |
11 | 5091837127 |
12 | 23a017a855 |
13 | 11896c2b78 |
14 | 817710253 |
15 | 4a0a99188 |
hex | 2c95ccb41 |
11968236353 has 4 divisors (see below), whose sum is σ = 11976222000. Its totient is φ = 11960250708.
The previous prime is 11968236349. The next prime is 11968236359. The reversal of 11968236353 is 35363286911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35363286911 = 30431 ⋅1162081.
It is a cyclic number.
It is not a de Polignac number, because 11968236353 - 22 = 11968236349 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11968236298 and 11968236307.
It is not an unprimeable number, because it can be changed into a prime (11968236359) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3990575 + ... + 3993572.
It is an arithmetic number, because the mean of its divisors is an integer number (2994055500).
Almost surely, 211968236353 is an apocalyptic number.
It is an amenable number.
11968236353 is a deficient number, since it is larger than the sum of its proper divisors (7985647).
11968236353 is an equidigital number, since it uses as much as digits as its factorization.
11968236353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7985646.
The product of its digits is 699840, while the sum is 47.
The spelling of 11968236353 in words is "eleven billion, nine hundred sixty-eight million, two hundred thirty-six thousand, three hundred fifty-three".
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