11970423503873 has 4 divisors (see below), whose sum is σ = 11971432230960. Its totient is φ = 11969414776788.

The previous prime is 11970423503851. The next prime is 11970423503921. The reversal of 11970423503873 is 37830532407911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11970423503873 - 2¹² = 11970423499777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11970423563873) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504345743 + ... + 504369476.

It is an arithmetic number, because the mean of its divisors is an integer number (2992858057740).

Almost surely, 2^{11970423503873} is an apocalyptic number.

It is an amenable number.

11970423503873 is a deficient number, since it is larger than the sum of its proper divisors (1008727087).

11970423503873 is a wasteful number, since it uses less digits than its factorization.

11970423503873 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008727086.

The product of its (nonzero) digits is 3810240, while the sum is 53.

The spelling of 11970423503873 in words is "eleven trillion, nine hundred seventy billion, four hundred twenty-three million, five hundred three thousand, eight hundred seventy-three".