Search a number
-
+
119711393 is a prime number
BaseRepresentation
bin1110010001010…
…10011010100001
322100020222011022
413020222122201
5221121231033
615513455225
72652346544
oct710523241
9270228138
10119711393
1161634a3a
1234111515
131ba55759
1411c8285b
15a79a098
hex722a6a1

119711393 has 2 divisors, whose sum is σ = 119711394. Its totient is φ = 119711392.

The previous prime is 119711369. The next prime is 119711407. The reversal of 119711393 is 393117911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113912929 + 5798464 = 10673^2 + 2408^2 .

It is a cyclic number.

It is not a de Polignac number, because 119711393 - 210 = 119710369 is a prime.

It is a super-2 number, since 2×1197113932 = 28661635228000898, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (119711323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59855696 + 59855697.

It is an arithmetic number, because the mean of its divisors is an integer number (59855697).

Almost surely, 2119711393 is an apocalyptic number.

It is an amenable number.

119711393 is a deficient number, since it is larger than the sum of its proper divisors (1).

119711393 is an equidigital number, since it uses as much as digits as its factorization.

119711393 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5103, while the sum is 35.

The square root of 119711393 is about 10941.2701730649. The cubic root of 119711393 is about 492.8466718412.

The spelling of 119711393 in words is "one hundred nineteen million, seven hundred eleven thousand, three hundred ninety-three".