Base | Representation |
---|---|
bin | 10110010011000101… |
… | …10010011111111011 |
3 | 1010220022001202201012 |
4 | 23021202302133323 |
5 | 144004121242442 |
6 | 5255521544135 |
7 | 602442104435 |
oct | 131142623773 |
9 | 33808052635 |
10 | 11971274747 |
11 | 50935219a3 |
12 | 23a11a504b |
13 | 118a217b33 |
14 | 817ca1655 |
15 | 4a0e99582 |
hex | 2c98b27fb |
11971274747 has 2 divisors, whose sum is σ = 11971274748. Its totient is φ = 11971274746.
The previous prime is 11971274741. The next prime is 11971274771. The reversal of 11971274747 is 74747217911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11971274747 - 214 = 11971258363 is a prime.
It is a super-2 number, since 2×119712747472 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11971274695 and 11971274704.
It is not a weakly prime, because it can be changed into another prime (11971274741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5985637373 + 5985637374.
It is an arithmetic number, because the mean of its divisors is an integer number (5985637374).
Almost surely, 211971274747 is an apocalyptic number.
11971274747 is a deficient number, since it is larger than the sum of its proper divisors (1).
11971274747 is an equidigital number, since it uses as much as digits as its factorization.
11971274747 is an evil number, because the sum of its binary digits is even.
The product of its digits is 691488, while the sum is 50.
The spelling of 11971274747 in words is "eleven billion, nine hundred seventy-one million, two hundred seventy-four thousand, seven hundred forty-seven".
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