Base | Representation |
---|---|
bin | 10110010011100100… |
… | …00001110011101001 |
3 | 1010220120120201122001 |
4 | 23021302001303221 |
5 | 144011132111414 |
6 | 5300143331001 |
7 | 602521053322 |
oct | 131162016351 |
9 | 33816521561 |
10 | 11975269609 |
11 | 5095800336 |
12 | 23a25b0a61 |
13 | 118acb6264 |
14 | 818621449 |
15 | 4a14d8074 |
hex | 2c9c81ce9 |
11975269609 has 2 divisors, whose sum is σ = 11975269610. Its totient is φ = 11975269608.
The previous prime is 11975269601. The next prime is 11975269643. The reversal of 11975269609 is 90696257911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8700225625 + 3275043984 = 93275^2 + 57228^2 .
It is a cyclic number.
It is not a de Polignac number, because 11975269609 - 23 = 11975269601 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11975269609.
It is not a weakly prime, because it can be changed into another prime (11975269601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5987634804 + 5987634805.
It is an arithmetic number, because the mean of its divisors is an integer number (5987634805).
Almost surely, 211975269609 is an apocalyptic number.
It is an amenable number.
11975269609 is a deficient number, since it is larger than the sum of its proper divisors (1).
11975269609 is an equidigital number, since it uses as much as digits as its factorization.
11975269609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1837080, while the sum is 55.
The spelling of 11975269609 in words is "eleven billion, nine hundred seventy-five million, two hundred sixty-nine thousand, six hundred nine".
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