Base | Representation |
---|---|
bin | 10110010100011110… |
… | …11101111011111001 |
3 | 1010221010002210220101 |
4 | 23022033131323321 |
5 | 144020121041001 |
6 | 5301020555401 |
7 | 602643465106 |
oct | 131217357371 |
9 | 33833083811 |
10 | 11982987001 |
11 | 509a0a1547 |
12 | 23a50b2b61 |
13 | 118c788b6b |
14 | 81966daad |
15 | 4a200ea01 |
hex | 2ca3ddef9 |
11982987001 has 2 divisors, whose sum is σ = 11982987002. Its totient is φ = 11982987000.
The previous prime is 11982986987. The next prime is 11982987007. The reversal of 11982987001 is 10078928911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6130890000 + 5852097001 = 78300^2 + 76499^2 .
It is an emirp because it is prime and its reverse (10078928911) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11982987001 - 221 = 11980889849 is a prime.
It is a super-2 number, since 2×119829870012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11982987007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5991493500 + 5991493501.
It is an arithmetic number, because the mean of its divisors is an integer number (5991493501).
Almost surely, 211982987001 is an apocalyptic number.
It is an amenable number.
11982987001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11982987001 is an equidigital number, since it uses as much as digits as its factorization.
11982987001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 46.
The spelling of 11982987001 in words is "eleven billion, nine hundred eighty-two million, nine hundred eighty-seven thousand, one".
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