11984485336058 has 4 divisors (see below), whose sum is σ = 17976728004090. Its totient is φ = 5992242668028.

The previous prime is 11984485336001. The next prime is 11984485336091. The reversal of 11984485336058 is 85063358448911.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11872248945769 + 112236390289 = 3445613^2 + 335017^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11984485335985 and 11984485336003.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2996121334013 + ... + 2996121334016.

Almost surely, 2^{11984485336058} is an apocalyptic number.

11984485336058 is a deficient number, since it is larger than the sum of its proper divisors (5992242668032).

11984485336058 is an equidigital number, since it uses as much as digits as its factorization.

11984485336058 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5992242668031.

The product of its (nonzero) digits is 99532800, while the sum is 65.

The spelling of 11984485336058 in words is "eleven trillion, nine hundred eighty-four billion, four hundred eighty-five million, three hundred thirty-six thousand, fifty-eight".