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1199134055441 = 7171304865063
BaseRepresentation
bin10001011100110001111…
…101011001110000010001
311020122011201021120100202
4101130301331121300101
5124121311304233231
62314512524224545
7152430442203230
oct21346175316021
94218151246322
101199134055441
11422605a05133
1217449769b155
138910208618a
1442077514b17
15212d3b895cb
hex11731f59c11

1199134055441 has 4 divisors (see below), whose sum is σ = 1370438920512. Its totient is φ = 1027829190372.

The previous prime is 1199134055419. The next prime is 1199134055447. The reversal of 1199134055441 is 1445504319911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1199134055441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1199134055447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85652432525 + ... + 85652432538.

It is an arithmetic number, because the mean of its divisors is an integer number (342609730128).

Almost surely, 21199134055441 is an apocalyptic number.

It is an amenable number.

1199134055441 is a deficient number, since it is larger than the sum of its proper divisors (171304865071).

1199134055441 is an equidigital number, since it uses as much as digits as its factorization.

1199134055441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171304865070.

The product of its (nonzero) digits is 388800, while the sum is 47.

The spelling of 1199134055441 in words is "one trillion, one hundred ninety-nine billion, one hundred thirty-four million, fifty-five thousand, four hundred forty-one".

Divisors: 1 7 171304865063 1199134055441