Base | Representation |
---|---|
bin | 10001011100111110011… |
… | …001100110101100001010 |
3 | 11020122201021000121211122 |
4 | 101130332121212230022 |
5 | 124122223222300200 |
6 | 2314545341555242 |
7 | 152435555245220 |
oct | 21347631465412 |
9 | 4218637017748 |
10 | 1199342775050 |
11 | 422702803282 |
12 | 174535575b22 |
13 | 891363a42c4 |
14 | 42097126b10 |
15 | 212e7167385 |
hex | 1173e666b0a |
1199342775050 has 96 divisors (see below), whose sum is σ = 2687581555200. Its totient is φ = 388989120960.
The previous prime is 1199342775047. The next prime is 1199342775077. The reversal of 1199342775050 is 505772439911.
It is a junction number, because it is equal to n+sod(n) for n = 1199342774983 and 1199342775001.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4409921 + ... + 4673979.
It is an arithmetic number, because the mean of its divisors is an integer number (27995641200).
Almost surely, 21199342775050 is an apocalyptic number.
1199342775050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1199342775050 is an abundant number, since it is smaller than the sum of its proper divisors (1488238780150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1199342775050 is a wasteful number, since it uses less digits than its factorization.
1199342775050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264780 (or 264775 counting only the distinct ones).
The product of its (nonzero) digits is 2381400, while the sum is 53.
The spelling of 1199342775050 in words is "one trillion, one hundred ninety-nine billion, three hundred forty-two million, seven hundred seventy-five thousand, fifty".
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