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11994133260937 is a prime number
BaseRepresentation
bin1010111010001001101000…
…0011010110101010001001
31120110121221202202212202111
42232202122003112222021
53033002441103322222
641302010113302321
72345355542366002
oct256423203265211
946417852685674
1011994133260937
1139047575a2a23
121418662b649a1
13690071111959
142d673a77c1a9
1515bedcd5c777
hexae89a0d6a89

11994133260937 has 2 divisors, whose sum is σ = 11994133260938. Its totient is φ = 11994133260936.

The previous prime is 11994133260919. The next prime is 11994133260943. The reversal of 11994133260937 is 73906233149911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8136322675776 + 3857810585161 = 2852424^2 + 1964131^2 .

It is an emirp because it is prime and its reverse (73906233149911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11994133260937 - 227 = 11993999043209 is a prime.

It is a super-2 number, since 2×119941332609372 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11994133260997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5997066630468 + 5997066630469.

It is an arithmetic number, because the mean of its divisors is an integer number (5997066630469).

Almost surely, 211994133260937 is an apocalyptic number.

It is an amenable number.

11994133260937 is a deficient number, since it is larger than the sum of its proper divisors (1).

11994133260937 is an equidigital number, since it uses as much as digits as its factorization.

11994133260937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6613488, while the sum is 58.

The spelling of 11994133260937 in words is "eleven trillion, nine hundred ninety-four billion, one hundred thirty-three million, two hundred sixty thousand, nine hundred thirty-seven".