Base | Representation |
---|---|
bin | 10110010110000100… |
… | …00000111010111001 |
3 | 1010222001001000011111 |
4 | 23023002000322321 |
5 | 144032014044442 |
6 | 5302213000321 |
7 | 603164223226 |
oct | 131302007271 |
9 | 33861030144 |
10 | 11996237497 |
11 | 50a6621872 |
12 | 23a96230a1 |
13 | 11924480aa |
14 | 81b31c94d |
15 | 4a327ab17 |
hex | 2cb080eb9 |
11996237497 has 2 divisors, whose sum is σ = 11996237498. Its totient is φ = 11996237496.
The previous prime is 11996237417. The next prime is 11996237509. The reversal of 11996237497 is 79473269911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11014292601 + 981944896 = 104949^2 + 31336^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11996237497 is a prime.
It is not a weakly prime, because it can be changed into another prime (11996237417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5998118748 + 5998118749.
It is an arithmetic number, because the mean of its divisors is an integer number (5998118749).
Almost surely, 211996237497 is an apocalyptic number.
It is an amenable number.
11996237497 is a deficient number, since it is larger than the sum of its proper divisors (1).
11996237497 is an equidigital number, since it uses as much as digits as its factorization.
11996237497 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5143824, while the sum is 58.
The spelling of 11996237497 in words is "eleven billion, nine hundred ninety-six million, two hundred thirty-seven thousand, four hundred ninety-seven".
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