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119963 is a prime number
BaseRepresentation
bin11101010010011011
320002120002
4131102123
512314323
62323215
71006514
oct352233
9202502
10119963
1182148
125950b
13427ac
1431a0b
1525828
hex1d49b

119963 has 2 divisors, whose sum is σ = 119964. Its totient is φ = 119962.

The previous prime is 119953. The next prime is 119971. The reversal of 119963 is 369911.

119963 is nontrivially palindromic in base 3.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-119963 is a prime.

It is a super-2 number, since 2×1199632 = 28782242738, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (119923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59981 + 59982.

It is an arithmetic number, because the mean of its divisors is an integer number (59982).

2119963 is an apocalyptic number.

119963 is a deficient number, since it is larger than the sum of its proper divisors (1).

119963 is an equidigital number, since it uses as much as digits as its factorization.

119963 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1458, while the sum is 29.

The square root of 119963 is about 346.3567524966. The cubic root of 119963 is about 49.3191715296.

The spelling of 119963 in words is "one hundred nineteen thousand, nine hundred sixty-three".