11999233 has 2 divisors, whose sum is σ = 11999234. Its totient is φ = 11999232.

The previous prime is 11999179. The next prime is 11999257. The reversal of 11999233 is 33299911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11370384 + 628849 = 3372^2 + 793^2 .

It is an emirp because it is prime and its reverse (33299911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11999233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11999192 and 11999201.

It is not a weakly prime, because it can be changed into another prime (11999293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5999616 + 5999617.

It is an arithmetic number, because the mean of its divisors is an integer number (5999617).

Almost surely, 2^11999233 is an apocalyptic number.

It is an amenable number.

11999233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11999233 is an equidigital number, since it uses as much as digits as its factorization.

11999233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13122, while the sum is 37.

The square root of 11999233 is about 3463.9909064546. The cubic root of 11999233 is about 228.9379706522.

The spelling of 11999233 in words is "eleven million, nine hundred ninety-nine thousand, two hundred thirty-three".