Base | Representation |
---|---|
bin | 11011010010001110101101… |
… | …010111110111111111001011 |
3 | 120201212212222022210000212111 |
4 | 123102032231113313333023 |
5 | 111212034444444444242 |
6 | 1103115123340523151 |
7 | 34163466603164044 |
oct | 3322165527677713 |
9 | 521785868700774 |
10 | 119999999999947 |
11 | 35265794674171 |
12 | 115609792504b7 |
13 | 51c5c4a429942 |
14 | 218c06106d8cb |
15 | dd171e655817 |
hex | 6d23ad5f7fcb |
119999999999947 has 2 divisors, whose sum is σ = 119999999999948. Its totient is φ = 119999999999946.
The previous prime is 119999999999941. The next prime is 120000000000031. The reversal of 119999999999947 is 749999999999911.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-119999999999947 is a prime.
It is not a weakly prime, because it can be changed into another prime (119999999999941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59999999999973 + 59999999999974.
It is an arithmetic number, because the mean of its divisors is an integer number (59999999999974).
Almost surely, 2119999999999947 is an apocalyptic number.
119999999999947 is a deficient number, since it is larger than the sum of its proper divisors (1).
119999999999947 is an equidigital number, since it uses as much as digits as its factorization.
119999999999947 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 878669669052, while the sum is 112.
The spelling of 119999999999947 in words is "one hundred nineteen trillion, nine hundred ninety-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred forty-seven".
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