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120001021201993 is a prime number
BaseRepresentation
bin11011010010001111101010…
…001111011100111001001001
3120201212222121111100110201111
4123102033222033130321021
5111212044042411430433
61103115412540450321
734163534113231351
oct3322175217347111
9521788544313644
10120001021201993
11352661690593a8
12115610032499a1
1351c6080b7b3c9
14218c11a939b61
15dd177e123dcd
hex6d23ea3dce49

120001021201993 has 2 divisors, whose sum is σ = 120001021201994. Its totient is φ = 120001021201992.

The previous prime is 120001021201981. The next prime is 120001021202089. The reversal of 120001021201993 is 399102120100021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110525755213129 + 9475265988864 = 10513123^2 + 3078192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120001021201993 is a prime.

It is not a weakly prime, because it can be changed into another prime (120001021204993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000510600996 + 60000510600997.

It is an arithmetic number, because the mean of its divisors is an integer number (60000510600997).

Almost surely, 2120001021201993 is an apocalyptic number.

It is an amenable number.

120001021201993 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001021201993 is an equidigital number, since it uses as much as digits as its factorization.

120001021201993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 31.

The spelling of 120001021201993 in words is "one hundred twenty trillion, one billion, twenty-one million, two hundred one thousand, nine hundred ninety-three".