12000110113 has 2 divisors, whose sum is σ = 12000110114. Its totient is φ = 12000110112.

The previous prime is 12000110081. The next prime is 12000110141. The reversal of 12000110113 is 31101100021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11576038464 + 424071649 = 107592^2 + 20593^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000110113 - 2⁵ = 12000110081 is a prime.

It is a super-4 number, since 4×12000110113⁴ (a number of 41 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12000110113.

It is not a weakly prime, because it can be changed into another prime (12000110153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000055056 + 6000055057.

It is an arithmetic number, because the mean of its divisors is an integer number (6000055057).

Almost surely, 2^12000110113 is an apocalyptic number.

It is an amenable number.

12000110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000110113 is an equidigital number, since it uses as much as digits as its factorization.

12000110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 12000110113 its reverse (31101100021), we get a palindrome (43101210134).

The spelling of 12000110113 in words is "twelve billion, one hundred ten thousand, one hundred thirteen".