Search a number
-
+
120001102020131 is a prime number
BaseRepresentation
bin11011010010001111101111…
…000011101111111000100011
3120201212222211010102110100212
4123102033233003233320203
5111212044224104121011
61103115424545004335
734163536114202633
oct3322175703577043
9521788733373325
10120001102020131
11352661aa739252
12115610263236ab
1351c6094836ca7
14218c1275766c3
15dd178628a08b
hex6d23ef0efe23

120001102020131 has 2 divisors, whose sum is σ = 120001102020132. Its totient is φ = 120001102020130.

The previous prime is 120001102020067. The next prime is 120001102020139. The reversal of 120001102020131 is 131020201100021.

It is a strong prime.

It is an emirp because it is prime and its reverse (131020201100021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120001102020131 - 26 = 120001102020067 is a prime.

It is a super-2 number, since 2×1200011020201312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120001102020139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000551010065 + 60000551010066.

It is an arithmetic number, because the mean of its divisors is an integer number (60000551010066).

Almost surely, 2120001102020131 is an apocalyptic number.

120001102020131 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001102020131 is an equidigital number, since it uses as much as digits as its factorization.

120001102020131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120001102020131 its reverse (131020201100021), we get a palindrome (251021303120152).

The spelling of 120001102020131 in words is "one hundred twenty trillion, one billion, one hundred two million, twenty thousand, one hundred thirty-one".