120001111122121 has 4 divisors (see below), whose sum is σ = 120008119321872. Its totient is φ = 119994102922372.

The previous prime is 120001111122083. The next prime is 120001111122169. The reversal of 120001111122121 is 121221111100021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120001111122121 - 2¹⁷ = 120001110991049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120001111122095 and 120001111122104.

It is not an unprimeable number, because it can be changed into a prime (120001114122121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3504074191 + ... + 3504108436.

It is an arithmetic number, because the mean of its divisors is an integer number (30002029830468).

Almost surely, 2^{120001111122121} is an apocalyptic number.

It is an amenable number.

120001111122121 is a deficient number, since it is larger than the sum of its proper divisors (7008199751).

120001111122121 is an equidigital number, since it uses as much as digits as its factorization.

120001111122121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7008199750.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 120001111122121 its reverse (121221111100021), we get a palindrome (241222222222142).

The spelling of 120001111122121 in words is "one hundred twenty trillion, one billion, one hundred eleven million, one hundred twenty-two thousand, one hundred twenty-one".