Base | Representation |
---|---|
bin | 11011010010001111101111… |
… | …100111001001110000001101 |
3 | 120201212222211202212222111200 |
4 | 123102033233213021300031 |
5 | 111212044233443114013 |
6 | 1103115425515540113 |
7 | 34163536256116146 |
oct | 3322175747116015 |
9 | 521788752788450 |
10 | 120001111301133 |
11 | 352662049a81a7 |
12 | 1156102945a639 |
13 | 51c60967364ca |
14 | 218c1288b0acd |
15 | dd1786ebee73 |
hex | 6d23ef9c9c0d |
120001111301133 has 48 divisors (see below), whose sum is σ = 182436091506240. Its totient is φ = 75912984387072.
The previous prime is 120001111301131. The next prime is 120001111301153. The reversal of 120001111301133 is 331103111100021.
120001111301133 is a `hidden beast` number, since 120 + 0 + 0 + 1 + 111 + 301 + 133 = 666.
It is not a de Polignac number, because 120001111301133 - 21 = 120001111301131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120001111301131) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3077685 + ... + 15794757.
It is an arithmetic number, because the mean of its divisors is an integer number (3800751906380).
Almost surely, 2120001111301133 is an apocalyptic number.
It is an amenable number.
120001111301133 is a deficient number, since it is larger than the sum of its proper divisors (62434980205107).
120001111301133 is a wasteful number, since it uses less digits than its factorization.
120001111301133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12717818 (or 12717815 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 120001111301133 its reverse (331103111100021), we get a palindrome (451104222401154).
The spelling of 120001111301133 in words is "one hundred twenty trillion, one billion, one hundred eleven million, three hundred one thousand, one hundred thirty-three".
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