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1200012213003 = 32112836698777
BaseRepresentation
bin10001011101100110010…
…011010011101100001011
311020201102220200121001220
4101131212103103230023
5124130111111304003
62315140014213123
7152461264340322
oct21354623235413
94221386617056
101200012213003
11422a1667898a
121746a17b41a3
1389211ca2936
144211bdc70b9
1521335cee353
hex117664d3b0b

1200012213003 has 16 divisors (see below), whose sum is σ = 1613280103296. Its totient is φ = 793403029440.

The previous prime is 1200012212929. The next prime is 1200012213011. The reversal of 1200012213003 is 3003122100021.

It is not a de Polignac number, because 1200012213003 - 212 = 1200012208907 is a prime.

It is a super-2 number, since 2×12000122130032 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1200012213073) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3170250 + ... + 3528527.

It is an arithmetic number, because the mean of its divisors is an integer number (100830006456).

Almost surely, 21200012213003 is an apocalyptic number.

1200012213003 is a deficient number, since it is larger than the sum of its proper divisors (413267890293).

1200012213003 is a wasteful number, since it uses less digits than its factorization.

1200012213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6699274.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1200012213003 its reverse (3003122100021), we get a palindrome (4203134313024).

The spelling of 1200012213003 in words is "one trillion, two hundred billion, twelve million, two hundred thirteen thousand, three".

Divisors: 1 3 211 283 633 849 59713 179139 6698777 20096331 1413441947 1895753891 4240325841 5687261673 400004071001 1200012213003