Base | Representation |
---|---|
bin | 11011010010010000101011… |
… | …001100110100111111101011 |
3 | 120201220002102110001122020211 |
4 | 123102100223030310333223 |
5 | 111212103310411031243 |
6 | 1103120113031401551 |
7 | 34163603115523231 |
oct | 3322205314647753 |
9 | 521802373048224 |
10 | 120002111033323 |
11 | 35266678258852 |
12 | 115612682232b7 |
13 | 51c61c58ab80c |
14 | 218c1c158c951 |
15 | dd17e4b4bd9d |
hex | 6d242b334feb |
120002111033323 has 4 divisors (see below), whose sum is σ = 120002155021080. Its totient is φ = 120002067045568.
The previous prime is 120002111033317. The next prime is 120002111033347. The reversal of 120002111033323 is 323330111200021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120002111033323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120002111033294 and 120002111033303.
It is not an unprimeable number, because it can be changed into a prime (120002111033303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17610565 + ... + 23454982.
It is an arithmetic number, because the mean of its divisors is an integer number (30000538755270).
Almost surely, 2120002111033323 is an apocalyptic number.
120002111033323 is a deficient number, since it is larger than the sum of its proper divisors (43987757).
120002111033323 is an equidigital number, since it uses as much as digits as its factorization.
120002111033323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43987756.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 120002111033323 its reverse (323330111200021), we get a palindrome (443332222233344).
The spelling of 120002111033323 in words is "one hundred twenty trillion, two billion, one hundred eleven million, thirty-three thousand, three hundred twenty-three".
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