Base | Representation |
---|---|
bin | 1010111010100000010001… |
… | …1100100001101111010001 |
3 | 1120111012122111021101211101 |
4 | 2232220010130201233101 |
5 | 3033102414040241423 |
6 | 41304453303544401 |
7 | 2345662320205120 |
oct | 256500434415721 |
9 | 46435574241741 |
10 | 12000213212113 |
11 | 3907297571265 |
12 | 141987b15b101 |
13 | 6907cc9217b9 |
14 | 2d6b5603dab7 |
15 | 15c2469d97ad |
hex | aea04721bd1 |
12000213212113 has 8 divisors (see below), whose sum is σ = 13714587817280. Its totient is φ = 10285853214960.
The previous prime is 12000213212069. The next prime is 12000213212171. The reversal of 12000213212113 is 31121231200021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12000213212113 - 213 = 12000213203921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12000213212173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1831158 + ... + 5230063.
It is an arithmetic number, because the mean of its divisors is an integer number (1714323477160).
Almost surely, 212000213212113 is an apocalyptic number.
It is an amenable number.
12000213212113 is a deficient number, since it is larger than the sum of its proper divisors (1714374605167).
12000213212113 is an equidigital number, since it uses as much as digits as its factorization.
12000213212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7304007.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12000213212113 its reverse (31121231200021), we get a palindrome (43121444412134).
The spelling of 12000213212113 in words is "twelve trillion, two hundred thirteen million, two hundred twelve thousand, one hundred thirteen".
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