1200030031113 has 8 divisors (see below), whose sum is σ = 1600455328128. Its totient is φ = 799812377424.

The previous prime is 1200030031069. The next prime is 1200030031153. The reversal of 1200030031113 is 3111300300021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1200030031113 - 2⁶ = 1200030031049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200030031092 and 1200030031101.

It is not an unprimeable number, because it can be changed into a prime (1200030031153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51897345 + ... + 51920462.

It is an arithmetic number, because the mean of its divisors is an integer number (200056916016).

Almost surely, 2^{1200030031113} is an apocalyptic number.

It is an amenable number.

1200030031113 is a deficient number, since it is larger than the sum of its proper divisors (400425297015).

1200030031113 is a wasteful number, since it uses less digits than its factorization.

1200030031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103821663.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1200030031113 its reverse (3111300300021), we get a palindrome (4311330331134).

The spelling of 1200030031113 in words is "one trillion, two hundred billion, thirty million, thirty-one thousand, one hundred thirteen".