Base | Representation |
---|---|
bin | 1010111010100001011110… |
… | …1000110100001010010011 |
3 | 1120111020110221011002201121 |
4 | 2232220113220310022103 |
5 | 3033104044002403103 |
6 | 41304545245143111 |
7 | 2346003310104361 |
oct | 256502750641223 |
9 | 46436427132647 |
10 | 12000535200403 |
11 | 39074422a3892 |
12 | 141994ab5aa97 |
13 | 69085154aa09 |
14 | 2d6b86ad8631 |
15 | 15c264ddd6bd |
hex | aea17a34293 |
12000535200403 has 4 divisors (see below), whose sum is σ = 12000560304040. Its totient is φ = 12000510096768.
The previous prime is 12000535200397. The next prime is 12000535200487. The reversal of 12000535200403 is 30400253500021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12000535200403 - 213 = 12000535192211 is a prime.
It is a super-2 number, since 2×120005352004032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12000535200803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11820558 + ... + 12795571.
It is an arithmetic number, because the mean of its divisors is an integer number (3000140076010).
Almost surely, 212000535200403 is an apocalyptic number.
12000535200403 is a deficient number, since it is larger than the sum of its proper divisors (25103637).
12000535200403 is an equidigital number, since it uses as much as digits as its factorization.
12000535200403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25103636.
The product of its (nonzero) digits is 3600, while the sum is 25.
Adding to 12000535200403 its reverse (30400253500021), we get a palindrome (42400788700424).
The spelling of 12000535200403 in words is "twelve trillion, five hundred thirty-five million, two hundred thousand, four hundred three".
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