1200101000433 has 16 divisors (see below), whose sum is σ = 1645936803840. Its totient is φ = 777411197136.

The previous prime is 1200101000419. The next prime is 1200101000443. The reversal of 1200101000433 is 3340001010021.

It is not a de Polignac number, because 1200101000433 - 2⁹ = 1200100999921 is a prime.

It is a super-2 number, since 2×1200101000433² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1200101000443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30596785 + ... + 30635982.

It is an arithmetic number, because the mean of its divisors is an integer number (102871050240).

Almost surely, 2^{1200101000433} is an apocalyptic number.

It is an amenable number.

1200101000433 is a deficient number, since it is larger than the sum of its proper divisors (445835803407).

1200101000433 is a wasteful number, since it uses less digits than its factorization.

1200101000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61232956.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1200101000433 its reverse (3340001010021), we get a palindrome (4540102010454).

The spelling of 1200101000433 in words is "one trillion, two hundred billion, one hundred one million, four hundred thirty-three", and thus it is an aban number.