Search a number
-
+
1200102010993 is a prime number
BaseRepresentation
bin10001011101101011101…
…001110111000001110001
311020201200011122210202101
4101131223221313001301
5124130302103322433
62315152543020401
7152463434532124
oct21355351670161
94221604583671
101200102010993
11422a623314a6
1217470789a701
1389227783942
1442129cc03bb
152133db3b07d
hex1176ba77071

1200102010993 has 2 divisors, whose sum is σ = 1200102010994. Its totient is φ = 1200102010992.

The previous prime is 1200102010951. The next prime is 1200102011023. The reversal of 1200102010993 is 3990102010021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 797363274304 + 402738736689 = 892952^2 + 634617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200102010993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1200102010903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600051005496 + 600051005497.

It is an arithmetic number, because the mean of its divisors is an integer number (600051005497).

Almost surely, 21200102010993 is an apocalyptic number.

It is an amenable number.

1200102010993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200102010993 is an equidigital number, since it uses as much as digits as its factorization.

1200102010993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 28.

Subtracting from 1200102010993 its product of nonzero digits (972), we obtain a palindrome (1200102010021).

The spelling of 1200102010993 in words is "one trillion, two hundred billion, one hundred two million, ten thousand, nine hundred ninety-three".