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12001031541153 = 324331010417419
BaseRepresentation
bin1010111010100011010100…
…1110001101000110100001
31120111021202112002211020100
42232220311032031012201
53033111103033304103
641305110415333013
72346021514661064
oct256506516150641
946437675084210
1012001031541153
113907677490a56
121419a69221169
13690900321375
142d6bd29ba8db
1515c2937825a3
hexaea3538d1a1

12001031541153 has 12 divisors (see below), whose sum is σ = 17737958764240. Its totient is φ = 7814625189336.

The previous prime is 12001031541151. The next prime is 12001031541181. The reversal of 12001031541153 is 35114513010021.

12001031541153 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 103 + 1 + 541 + 15 + 3 = 666.

It is not a de Polignac number, because 12001031541153 - 21 = 12001031541151 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12001031541151) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15505208323 + ... + 15505209096.

Almost surely, 212001031541153 is an apocalyptic number.

It is an amenable number.

12001031541153 is a deficient number, since it is larger than the sum of its proper divisors (5736927223087).

12001031541153 is a wasteful number, since it uses less digits than its factorization.

12001031541153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31010417468 (or 31010417465 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 12001031541153 its reverse (35114513010021), we get a palindrome (47115544551174).

The spelling of 12001031541153 in words is "twelve trillion, one billion, thirty-one million, five hundred forty-one thousand, one hundred fifty-three".

Divisors: 1 3 9 43 129 387 31010417419 93031252257 279093756771 1333447949017 4000343847051 12001031541153