12001102133131 has 4 divisors (see below), whose sum is σ = 12414933241200. Its totient is φ = 11587271025064.

The previous prime is 12001102133077. The next prime is 12001102133147. The reversal of 12001102133131 is 13133120110021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12001102133131 - 2¹⁹ = 12001101608843 is a prime.

It is a super-2 number, since 2×12001102133131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12001102133099 and 12001102133108.

It is not an unprimeable number, because it can be changed into a prime (12001102133161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206915553991 + ... + 206915554048.

It is an arithmetic number, because the mean of its divisors is an integer number (3103733310300).

Almost surely, 2^{12001102133131} is an apocalyptic number.

12001102133131 is a deficient number, since it is larger than the sum of its proper divisors (413831108069).

12001102133131 is an equidigital number, since it uses as much as digits as its factorization.

12001102133131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413831108068.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 12001102133131 its reverse (13133120110021), we get a palindrome (25134222243152).

The spelling of 12001102133131 in words is "twelve trillion, one billion, one hundred two million, one hundred thirty-three thousand, one hundred thirty-one".