Base | Representation |
---|---|
bin | 11011010010011001000011… |
… | …000011101000010111000011 |
3 | 120201220221121222122221021021 |
4 | 123102121003003220113003 |
5 | 111212230213402210201 |
6 | 1103124201102210311 |
7 | 34164341652002062 |
oct | 3322310303502703 |
9 | 521827558587237 |
10 | 120011101210051 |
11 | 3526a470a4a677 |
12 | 11562b56b83997 |
13 | 51c6cc92cc80c |
14 | 218c7d55681d9 |
15 | dd1b6e037ea1 |
hex | 6d26430e85c3 |
120011101210051 has 2 divisors, whose sum is σ = 120011101210052. Its totient is φ = 120011101210050.
The previous prime is 120011101210009. The next prime is 120011101210183. The reversal of 120011101210051 is 150012101110021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120011101210051 - 215 = 120011101177283 is a prime.
It is not a weakly prime, because it can be changed into another prime (120011104210051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005550605025 + 60005550605026.
It is an arithmetic number, because the mean of its divisors is an integer number (60005550605026).
Almost surely, 2120011101210051 is an apocalyptic number.
120011101210051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120011101210051 is an equidigital number, since it uses as much as digits as its factorization.
120011101210051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 120011101210051 its reverse (150012101110021), we get a palindrome (270023202320072).
The spelling of 120011101210051 in words is "one hundred twenty trillion, eleven billion, one hundred one million, two hundred ten thousand, fifty-one".
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