120011956258307 has 2 divisors, whose sum is σ = 120011956258308. Its totient is φ = 120011956258306.

The previous prime is 120011956258277. The next prime is 120011956258349. The reversal of 120011956258307 is 703852659110021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120011956258307 - 2²² = 120011952064003 is a prime.

It is not a weakly prime, because it can be changed into another prime (120011952258307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005978129153 + 60005978129154.

It is an arithmetic number, because the mean of its divisors is an integer number (60005978129154).

Almost surely, 2^{120011956258307} is an apocalyptic number.

120011956258307 is a deficient number, since it is larger than the sum of its proper divisors (1).

120011956258307 is an equidigital number, since it uses as much as digits as its factorization.

120011956258307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 907200, while the sum is 50.

The spelling of 120011956258307 in words is "one hundred twenty trillion, eleven billion, nine hundred fifty-six million, two hundred fifty-eight thousand, three hundred seven".