Base | Representation |
---|---|
bin | 11011010010011010000110… |
… | …011010101101000010100010 |
3 | 120201221001112202012002010211 |
4 | 123102122012122231002202 |
5 | 111212240022210111002 |
6 | 1103124505152444334 |
7 | 34164411653612212 |
oct | 3322320632550242 |
9 | 521831482162124 |
10 | 120012231332002 |
11 | 3526a9a0968a59 |
12 | 115632115496aa |
13 | 51c7149498b29 |
14 | 218c8a16a8242 |
15 | dd1bd836ddd7 |
hex | 6d26866ad0a2 |
120012231332002 has 4 divisors (see below), whose sum is σ = 180018346998006. Its totient is φ = 60006115666000.
The previous prime is 120012231331997. The next prime is 120012231332009. The reversal of 120012231332002 is 200233132210021.
120012231332002 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 119960520117201 + 51711214801 = 10952649^2 + 227401^2 .
It is not an unprimeable number, because it can be changed into a prime (120012231332009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30003057832999 + ... + 30003057833002.
Almost surely, 2120012231332002 is an apocalyptic number.
120012231332002 is a deficient number, since it is larger than the sum of its proper divisors (60006115666004).
120012231332002 is an equidigital number, since it uses as much as digits as its factorization.
120012231332002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60006115666003.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 120012231332002 its reverse (200233132210021), we get a palindrome (320245363542023).
The spelling of 120012231332002 in words is "one hundred twenty trillion, twelve billion, two hundred thirty-one million, three hundred thirty-two thousand, two".
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