12001231122019 has 4 divisors (see below), whose sum is σ = 12001688564544. Its totient is φ = 12000773679496.

The previous prime is 12001231122007. The next prime is 12001231122029. The reversal of 12001231122019 is 91022113210021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12001231122019 is a prime.

It is a super-3 number, since 3×12001231122019³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12001231121984 and 12001231122002.

It is not an unprimeable number, because it can be changed into a prime (12001231122029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 228681907 + ... + 228734380.

It is an arithmetic number, because the mean of its divisors is an integer number (3000422141136).

Almost surely, 2^{12001231122019} is an apocalyptic number.

12001231122019 is a deficient number, since it is larger than the sum of its proper divisors (457442525).

12001231122019 is an equidigital number, since it uses as much as digits as its factorization.

12001231122019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 457442524.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 12001231122019 in words is "twelve trillion, one billion, two hundred thirty-one million, one hundred twenty-two thousand, nineteen".